SOLUTION: 3) The lengths of the sides of an irregular octagon are measured in metres and are given by the following expressions: x, (x -2), (x -3), (x + 5), 3x -2, 6, 2x + 8 and 2(x +5).

Algebra ->  Expressions -> SOLUTION: 3) The lengths of the sides of an irregular octagon are measured in metres and are given by the following expressions: x, (x -2), (x -3), (x + 5), 3x -2, 6, 2x + 8 and 2(x +5).       Log On


   

Question 177535: 3) The lengths of the sides of an irregular octagon are measured in metres and are given by the following expressions:
x, (x -2), (x -3), (x + 5), 3x -2, 6, 2x + 8 and 2(x +5).
a) Create an equation for the perimeter P of the octagon and then simplify the expression.
The total length of the perimeter of the octagon is 86m.
b) use your answer to part a) to find x and the length of al the sides of the octagon.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
A.)The perimeter of the octagon is the sum of its sides.

P=x%2Bx-2%2Bx-3%2Bx%2B5%2B3x-2%2B6%2B2x%2B8%2B2x%2B10
P=%28x%2Bx%2Bx%2Bx%2B3x%2B2x%2B2x%29%2B%28-2-3%2B5-2%2B6%2B8%2B10%29
P=11x%2B22
.
.
.
B.)P=11x%2B22=86
11x=64
x=64%2F11
.
.
.
Side 1: x=64%2F11
Side 2: x-2=64%2F11-22%2F11=42%2F11
Side 3: x-3=64%2F11-33%2F11=31%2F11
Side 4: x%2B5=64%2F11%2B55%2F11=119%2F11
Side 5: 3x-2=3%2864%2F11%29-22%2F11=192%2F11-22%2F11=170%2F11
Side 6: x=6
Side 7: x=2x%2B8=2%2864%2F11%29%2B88%2F11=128%2F11%2B88%2F11=216%2F11
Side 8: x=2%28x%2B5%29=2%28119%2F11%29=238%2F11