SOLUTION: i'm suppose to factor completely and can you please show the steps, thank you 61) 12x3 + 16x2 – 400x 62) x3 + 3x2 + 2x + 6 63) x2 – 3x + 2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: i'm suppose to factor completely and can you please show the steps, thank you 61) 12x3 + 16x2 – 400x 62) x3 + 3x2 + 2x + 6 63) x2 – 3x + 2       Log On


   



Question 177243: i'm suppose to factor completely and can you please show the steps, thank you

61) 12x3 + 16x2 – 400x

62) x3 + 3x2 + 2x + 6

63) x2 – 3x + 2

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 61



12x%5E3%2B16x%5E2-400x Start with the given expression


4x%283x%5E2%2B4x-100%29 Factor out the GCF 4x


Now let's try to factor the inner expression 3x%5E2%2B4x-100




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Looking at 3x%5E2%2B4x-100 we can see that the first term is 3x%5E2 and the last term is -100 where the coefficients are 3 and -100 respectively.

Now multiply the first coefficient 3 and the last coefficient -100 to get -300. Now what two numbers multiply to -300 and add to the middle coefficient 4? Let's list all of the factors of -300:



Factors of -300:
1,2,3,4,5,6,10,12,15,20,25,30,50,60,75,100,150,300

-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-25,-30,-50,-60,-75,-100,-150,-300 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -300
(1)*(-300)
(2)*(-150)
(3)*(-100)
(4)*(-75)
(5)*(-60)
(6)*(-50)
(10)*(-30)
(12)*(-25)
(15)*(-20)
(-1)*(300)
(-2)*(150)
(-3)*(100)
(-4)*(75)
(-5)*(60)
(-6)*(50)
(-10)*(30)
(-12)*(25)
(-15)*(20)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4

First NumberSecond NumberSum
1-3001+(-300)=-299
2-1502+(-150)=-148
3-1003+(-100)=-97
4-754+(-75)=-71
5-605+(-60)=-55
6-506+(-50)=-44
10-3010+(-30)=-20
12-2512+(-25)=-13
15-2015+(-20)=-5
-1300-1+300=299
-2150-2+150=148
-3100-3+100=97
-475-4+75=71
-560-5+60=55
-650-6+50=44
-1030-10+30=20
-1225-12+25=13
-1520-15+20=5

None of these pairs of factors add to 4. So the expression 3x%5E2%2B4x-100 cannot be factored

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Answer:
So 12x%5E3%2B16x%5E2-400x factors to 4x%283x%5E2%2B4x-100%29





# 62



x%5E3%2B3x%5E2%2B2x%2B6 Start with the given expression


%28x%5E3%2B3x%5E2%29%2B%282x%2B6%29 Group like terms


x%5E2%28x%2B3%29%2B2%28x%2B3%29 Factor out the GCF x%5E2 out of the first group. Factor out the GCF 2 out of the second group


%28x%5E2%2B2%29%28x%2B3%29 Since we have the common term x%2B3, we can combine like terms


So x%5E3%2B3x%5E2%2B2x%2B6 factors to %28x%5E2%2B2%29%28x%2B3%29


In other words, x%5E3%2B3x%5E2%2B2x%2B6=%28x%5E2%2B2%29%28x%2B3%29







# 63




Looking at the expression x%5E2-3x%2B2, we can see that the first coefficient is 1, the second coefficient is -3, and the last term is 2.


Now multiply the first coefficient 1 by the last term 2 to get %281%29%282%29=2.


Now the question is: what two whole numbers multiply to 2 (the previous product) and add to the second coefficient -3?


To find these two numbers, we need to list all of the factors of 2 (the previous product).


Factors of 2:
1,2
-1,-2


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 2.
1*2
(-1)*(-2)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -3:


First NumberSecond NumberSum
121+2=3
-1-2-1+(-2)=-3



From the table, we can see that the two numbers -1 and -2 add to -3 (the middle coefficient).


So the two numbers -1 and -2 both multiply to 2 and add to -3


Now replace the middle term -3x with -x-2x. Remember, -1 and -2 add to -3. So this shows us that -x-2x=-3x.


x%5E2%2Bhighlight%28-x-2x%29%2B2 Replace the second term -3x with -x-2x.


%28x%5E2-x%29%2B%28-2x%2B2%29 Group the terms into two pairs.


x%28x-1%29%2B%28-2x%2B2%29 Factor out the GCF x from the first group.


x%28x-1%29-2%28x-1%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x-2%29%28x-1%29 Combine like terms. Or factor out the common term x-1

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Answer:


So x%5E2-3x%2B2 factors to %28x-2%29%28x-1%29.


In other words, x%5E2-3x%2B2=%28x-2%29%28x-1%29


Note: you can check the answer by FOILing %28x-2%29%28x-1%29 to get x%5E2-3x%2B2 or by graphing the original expression and the answer (the two graphs should be identical).