SOLUTION: For the function, g(x)=2x^3-3x^2-9x+8/2x-1, I used long division and got: y=x^2-x-5.
So how do you find the vertex of the parabolic asymptote?
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Polynomials-and-rational-expressions
-> SOLUTION: For the function, g(x)=2x^3-3x^2-9x+8/2x-1, I used long division and got: y=x^2-x-5.
So how do you find the vertex of the parabolic asymptote?
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Question 177119: For the function, g(x)=2x^3-3x^2-9x+8/2x-1, I used long division and got: y=x^2-x-5.
So how do you find the vertex of the parabolic asymptote? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! For the function, g(x)=2x^3-3x^2-9x+8/2x-1, I used long division and got: y=x^2-x-5.
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Yes, but with a remainder of -3.
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So how do you find the vertex of the parabolic asymptote?
Of what parabola?
