SOLUTION: Solve the logarithmic equation algebraically approximately 3 decimal places Ln x-Ln(x+1)=2 Thank you!

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Question 176950This question is from textbook Algebra & Trigonometry
: Solve the logarithmic equation algebraically approximately 3 decimal places
Ln x-Ln(x+1)=2

Thank you! This question is from textbook Algebra & Trigonometry

Found 2 solutions by nerdybill, stanbon:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Ln x-Ln(x+1)=2
Ln x/(x+1)=2
x/(x+1)=e^2
x=e^2(x+1)
x=xe^2+e^2
x-xe^2=e^2
x(1-e^2)=e^2
x = e^2/(1-e^2)
x = -1.157



Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Ln x-Ln(x+1)=2
ln[x/(x+1)] = 2
x/(x+1) = e^2
x = (e^2)x + e^2
(1-e^2)x = e^2
x = -1.1565176
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But ln of a negative does not exist.
So, there are no solutions.
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Cheers,
Stan H.


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Cheers,
Stan H.