SOLUTION: Two lines have the following equations. 2x+y = 4 3y = 2x - 12 At what point do these lines intersect? please help thanks!!

Click here to see ALL problems on Equations

Question 176917: Two lines have the following equations.

2x+y = 4
3y = 2x - 12

At what point do these lines intersect?

please help thanks!!
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
2x+y = 4
3y = 2x - 12
At what point do these lines intersect?
--------------------------------------------
Rearrange:
y = -2x + 4
y = (2/3)x - 4
--------------------
Substitute to get:
-2x+4 = (2/3)x - 4
(8/3)x = 8
(1/3)x = 1
x = 3
----------
Since y = -2x + 4, y = -2*3 + 4 = -2
=============================
Solution: (3,-2)
=======================
Cheers,
Stan H.

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Two lines have the following equations.
2x+y = 4
3y = 2x - 12 --> 2x = 3y+12
---------
Sub 2x into the 1st eqn
2x+y = 4
3y+12 + y = 4
4y+12 = 4
4y = -8
y = -2
----------
2x-2 = 4 (1st eqn)
2x = 6
x = 3
------
The values of x and y that "satisfy", or fit, both eqns is where they intersect.
That's at (3,-2)