SOLUTION: factor: 12) 15x^5 - 2x^4 - x³ 13) 49y4-25

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Question 176861: factor:
12) 15x^5 - 2x^4 - x³

13) 49y4-25
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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12) 15x^5 - 2x^4 - x³
:
factor out x^3
x^3(15x^2 + 2x - 1)
:
Quadratic factors so we have
x^3(5x - 1)(3x + 1)
:
:
13) 49y4-25
:
this is the difference of squares
(7y^2 + 5)(7y^2 - 5)