SOLUTION: Hello. I am having serious trouble on this one. THE SUM OF THREE CONSECUTIVE ODD INTEGERS IS 639. WHAT ARE THE INTEGERS? Thank you.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Hello. I am having serious trouble on this one. THE SUM OF THREE CONSECUTIVE ODD INTEGERS IS 639. WHAT ARE THE INTEGERS? Thank you.      Log On


   

Question 17686: Hello. I am having serious trouble on this one. THE SUM OF THREE CONSECUTIVE ODD INTEGERS IS 639. WHAT ARE THE INTEGERS? Thank you.
Found 2 solutions by mukku, pwac:
Answer by mukku(2) About Me  (Show Source):
You can put this solution on YOUR website!
Hi
Here's the answer:
Consider n be the 1st integer.
The next in the series is n+2.
then the next will be n+4.
thus n+n+2+n+4= 639
3n+6=639
3n=633
n=633/3=211
the integers are 211, 213, 215:)

Answer by pwac(253) About Me  (Show Source):
You can put this solution on YOUR website!
let(2n+1) = first number.this is always odd
(2n+1)+(2n+3)+(2n+5)=639
6n+9=639 subtract 9 from both sides
6n=630 divide both sides by 6
n=105
2n+1=211
2n+3=213
2n+5=215
three odd integers that add to 639
Pete