SOLUTION: Thank you in advance for helping me with this problem. (4^x)(16^3x-1)=8 This is what I have done. (2^2x)(2^4(3x-1))=2^3 in the end I got 2/7??? am I on the right track? thank

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Thank you in advance for helping me with this problem. (4^x)(16^3x-1)=8 This is what I have done. (2^2x)(2^4(3x-1))=2^3 in the end I got 2/7??? am I on the right track? thank      Log On


   

Question 176826This question is from textbook college algebras
: Thank you in advance for helping me with this problem. (4^x)(16^3x-1)=8
This is what I have done.
(2^2x)(2^4(3x-1))=2^3
in the end I got 2/7??? am I on the right track? thanks for your help.


This question is from textbook college algebras

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
%284%5Ex%29%2816%5E%283x-1%29%29+=+8 Your first step is good!
%282%5E%282x%29%29%282%5E%284%283x-1%29%29%29+=+2%5E3 Expand the second exponent.
%282%5E%282x%29%29%282%5E%2812x-4%29%29+=+2%5E8 The second factor on the left shows the exponents being subtracted so this means division:
%282%5E%282x%29%29%28%282%5E%2812x%29%29%2F2%5E4%29+=+2%5E3 Multiply both sides by 2%5E4
%282%5E%282x%29%29%282%5E%2812x%29%29+=+%282%5E3%29%282%5E4%29 Perform the indicated multiplication by adding the exponents.
2%5E%2814x%29+=+2%5E7 The bases (2) are equal so the exponents are equal.
14x+=+7 Divide both sides by 14.
highlight%28x+=+1%2F2%29