SOLUTION: Thank you in advance for helping me with this problem. (1/8)^-2t=2^t+3

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Thank you in advance for helping me with this problem. (1/8)^-2t=2^t+3       Log On


   

Question 176825This question is from textbook college algebras
: Thank you in advance for helping me with this problem.
(1/8)^-2t=2^t+3
This question is from textbook college algebras

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%281%2F8%29%5E%28-2t%29=2%5E%28t%2B3%29 Start with the given equation.


%282%5E%28-3%29%29%5E%28-2t%29=2%5E%28t%2B3%29 Rewrite 1%2F8 as 1%2F8=8%5E%28-1%29=%282%5E3%29%5E%28-1%29=2%5E%28-3%29


2%5E%286t%29=2%5E%28t%2B3%29 Multiply the exponents.


Since the bases are equal, the exponents are equal.


6t=t%2B3 Set the exponents equal to one another.


6t-t=3 Subtract t from both sides.


5t=3 Combine like terms on the left side.


t=%283%29%2F%285%29 Divide both sides by 5 to isolate t.


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Answer:

So the answer is t=3%2F5