SOLUTION: the perimeter of a rectangle is 44 inches.find the dimensions if the width is two inches longer than three times the length.then find the area of the rectangle.

Click here to see ALL problems on Rectangles

Question 176755: the perimeter of a rectangle is 44 inches.find the dimensions if the width is two inches longer than three times the length.then find the area of the rectangle.
Found 2 solutions by ankor@dixie-net.com, josmiceli:
Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
the perimeter of a rectangle is 44 inches.find the dimensions if the width is two inches longer than three times the length.then find the area of the rectangle
;
2L + 2W = 44
simplify, divide by 2
L + W = 22
:
It says; the width is two inches longer than three times the length."
The equation for this statement is:
W = 3L + 2
:
substitute (3L+2) for W
L + (3L+2) = 22
4L = 22 - 2
4L = 20
L =
L = 5 in
:
W = 3L + 2
W = 3(5) + 2
W = 17 in
;
find the area: 17 * 5 = 85 sq/in
;
;
check solutions by finding the perimeter
2(5) + 2(17) = 44

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
If = length
If = width
The perimeter is or

given:
(1) in
(2) in
substitute (2) in (1)

in
and from (2)
(2)

in
The width is 17 in and length is 5 in
check:
(1) in

(2) in

OK