SOLUTION: twice the smallest of three consecutive odd integers is 7 more than the largest.

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Question 176657: twice the smallest of three consecutive odd integers is 7 more than the largest.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
let the integers be a,a+2,a+4
:
2a=a+4+7
:
a=11
:
integerssystem%2811%2C13%2C15%29