SOLUTION: G(x)=/1-x/-/3x+7/

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Question 176583: G(x)=/1-x/-/3x+7/
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming the brackets signify absolute value??
Break the problem down into 3 distinct regions based on the arguments of the absolute value functions.
3x%2B7%3C0
3x%3C-7
x%3C-7%2F3
.
.
.
1-x%3C0
-x%3C-1
x%3E1
.
.
.
and in between these two regions.
-7%2F3%3Cx%3C1
In the region where x<-7/3
abs%281-x%29=%281-x%29
abs%283x%2B7%29=-%283x%2B7%29
The function then becomes
G%28x%29=%281-x%29-%28-%283x%2B7%29%29
G%28x%29=%281-x%29%2B%283x%2B7%29%29
G%28x%29=2x%2B8
.
.
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In the region where x>1, then
abs%281-x%29=-%281-x%29
abs%283x%2B7%29=%283x%2B7%29
The function then becomes
G%28x%29=-%281-x%29-%283x%2B7%29
G%28x%29=-1%2Bx-3x-7%29%29
G%28x%29=+-2x-8
.
.
.
Finally in between these two regions.
-7%2F3%3Cx%3C1
abs%281-x%29=%281-x%29
abs%283x%2B7%29=%283x%2B7%29
The function then becomes
G%28x%29=%281-x%29-%283x%2B7%29
G%28x%29=+-4x-6%29%29

Red : G(x)=2x+8
Blue :G(x)= -4x-6
Green :G(x)=-2x-8
The circles show the break points of x=-7/3 and x=1.
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.
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Here is the graph trimmed of the extraneous regions.
+graph%28+300%2C+300%2C+-5%2C+4%2C+-15%2C+10%2C+abs%281-x%29-abs%283x%2B7%29%29+