SOLUTION: Evaluate: a) [16^1/2 + (2/3)^0]^-2 b) (7^0 - 4^-1)^-3 c) (5^-2 + 4^0)^-1 d) -8^0 + (-2/3)^-2

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Evaluate: a) [16^1/2 + (2/3)^0]^-2 b) (7^0 - 4^-1)^-3 c) (5^-2 + 4^0)^-1 d) -8^0 + (-2/3)^-2      Log On


   

Question 176517: Evaluate:
a) [16^1/2 + (2/3)^0]^-2
b) (7^0 - 4^-1)^-3
c) (5^-2 + 4^0)^-1
d) -8^0 + (-2/3)^-2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Remember any expression raised to the zero power equals 1.
x%5E0=1
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a) %2816%5E%281%2F2%29+%2B+%282%2F3%29%5E0%29%5E%28-2%29
Let's take it piece by piece.
Remember, square roots have both positive and negative solutions.
16%5E%281%2F2%29=4 and 16%5E%281%2F2%29=-4
%282%2F3%29%5E0=1
Put it all together
1.Positive :
2.Negative :
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b) %287%5E%280%29+-+4%5E%28-1%29%29%5E%28-3%29
7%5E%280%29=1
4%5E%28-1%29=1%2F4

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c.) %285%5E%28-2%29+%2B+4%5E%280%29%29%5E%28-1%29
5%5E%28-2%29=1%2F25
4%5E%280%29=1

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d.) -8%5E%280%29+%2B+%28-2%2F3%29%5E%28-2%29
-8%5E%280%29=1
%28%28-2%29%2F3%29%5E%28-2%29=%283%2F%28-2%29%29%5E%282%29=9%2F4
-8%5E%280%29+%2B+%28-2%2F3%29%5E%28-2%29=1%2B9%2F4=13%2F4