SOLUTION: can you help with this problem:
ten gallons of a 30% acid mixture is obtained by mixing a 20% solution with a 50% solution. How much of each must be used?
i've tried creating
Question 176462: can you help with this problem:
ten gallons of a 30% acid mixture is obtained by mixing a 20% solution with a 50% solution. How much of each must be used?
i've tried creating two linear equations (one for total volume and one for concentration) but i don't know where to go from there. Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! ok lets call the amount of 20% and 50% solutions a and b respectively
:
a+b=10...........eq 1
.2a+.5b=.3(10)...eq 2
:
rewrite eq 1 to a=10-b and plug this value into eq 2
:
.2(10-b)+.5b=3
:
2-.2b+.5b=3
:
.3b=1
: amount of 50% solution
: amount of 20% solution