SOLUTION: a can contains 3 tennis ball, tightly packed. each ball has a diameter of 2.5 in. how much greater is the circumference of the can than the height of the can?
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Question 176446: a can contains 3 tennis ball, tightly packed. each ball has a diameter of 2.5 in. how much greater is the circumference of the can than the height of the can? Answer by MathTherapy(10553) (Show Source):
You can put this solution on YOUR website! a can contains 3 tennis ball, tightly packed. each ball has a diameter of 2.5 in. how much greater is the circumference of the can than the height of the can?
Circumference of top or bottom circle of can = piD = 2.5pi inches = 7.86 inches
Height of can = 3 * 2.5 = 7.5 inches
Therefore, circumference (7.86 inches) is .36 inches greater than the height (7.5 inches) of the can.
