SOLUTION: I am havin a hard time learning how to "aproximate a logarithm to the nearest thousandth" I have a problem that is log(base 5) of 9 and all I did was divide 9 by 5 two times since

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I am havin a hard time learning how to "aproximate a logarithm to the nearest thousandth" I have a problem that is log(base 5) of 9 and all I did was divide 9 by 5 two times since      Log On


   



Question 176289: I am havin a hard time learning how to "aproximate a logarithm to the nearest thousandth" I have a problem that is log(base 5) of 9 and all I did was divide 9 by 5 two times since that got me to one.actually, .36. but i dont think I even did that right. please help
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I am havin a hard time learning how to "aproximate a logarithm to the nearest thousandth" I have a problem that is log(base 5) of 9
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log%285%2C9%29+=+log%289%29%2Flog%285%29 (log base 10 unless otherwise indicated)
log%285%2C9%29+=+0.95424...%2F0.69897...
=~ 1.365...
As a proof,
5%5E1.365+=+8.9969..., apx 9