SOLUTION: please help me solve interval notation. |3x+4| > 11. Thank you

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Question 176220: please help me solve interval notation.

|3x+4| > 11. Thank you

Found 2 solutions by solver91311, stanbon:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
abs%283x+%2B+4%29+%3E+11 means that 3x+%2B+4+%3E+11 or -%283x+%2B+4%29+%3E+11

So: 3x+%2B+4+%3E+113x+%3E+11+-+4x+%3E+7%2F3

or: -3x+-+4+%3E+11-3x+%3E+11+%2B+4x+%3C+-15%2F3+=+-5 (Note sense change on the inequality because of multiplying by a -1%2F3

Interval notation:

(-infinity,-5) (7%2F3,infinity)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve interval notation.
|3x+4| > 11
solve interval notation.
|3x+4| > 11
3x+4 < -11 or 3x+4 > 11
x < -5 or x > 7/3
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(-inf,-5) U (7/3,+ inf)
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Cheers,
Stan H.