SOLUTION: (4x10^-11)x(7x10^6)=28x10^-5=2.8x10^-4=0.00028 my question:how does the decimal point get there (2.8) and why has the exponent (10) been decreased?

Algebra ->  Exponents -> SOLUTION: (4x10^-11)x(7x10^6)=28x10^-5=2.8x10^-4=0.00028 my question:how does the decimal point get there (2.8) and why has the exponent (10) been decreased?      Log On


   

Question 176124This question is from textbook BARRONS ALGEBRA THE EASY WAY
: (4x10^-11)x(7x10^6)=28x10^-5=2.8x10^-4=0.00028
my question:how does the decimal point get there (2.8) and why has the exponent (10) been decreased? This question is from textbook BARRONS ALGEBRA THE EASY WAY

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%284x10%5E%28-11%29%29%2A%287x10%5E%286%29%29=28x10%5E%28-11%2B6%29
%284x10%5E%28-11%29%29%2A%287x10%5E%286%29%29=28x10%5E%28-5%29
Replace 28 with 2.8x10%5E1
%284x10%5E%28-11%29%29%2A%287x10%5E%286%29%29=2.8x10%5E%281%29%2A10%5E%28-5%29
%284x10%5E%28-11%29%29%2A%287x10%5E%286%29%29=2.8x10%5E%281-5%29
%284x10%5E%28-11%29%29%2A%287x10%5E%286%29%29=2.8x10%5E%28-4%29
Traditionally, the coefficient in scientific notation takes on values between 1 and 10. That's why 28 was replaced with 2.8x10^1. But the values are identical, as are all of the values below.
280x10%5E%28-6%29
28x10%5E%28-5%29
2.8x10%5E%28-4%29
.28x10%5E%28-3%29
.028x10%5E%28-2%29
.0028x10%5E%28-1%29
.00028