SOLUTION: The formula gives the height h in feet of an object after t seconds. Here is the initial velocity of the object expressed in feet per second. Suppose a toy rocket was launched
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Question 176111: The formula gives the height h in feet of an object after t seconds. Here is the initial velocity of the object expressed in feet per second. Suppose a toy rocket was launched from the ground straight up with an initial velocity of 64 ft/sec. How many seconds after launch was the rocket 48 feet above the ground? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The formula gives the height h in feet of an object after t seconds. Here is the initial velocity of the object expressed in feet per second. Suppose a toy rocket was launched from the ground straight up with an initial velocity of 64 ft/sec. How many seconds after launch was the rocket 48 feet above the ground?
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h(t) = -16t^2 + 64t
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-16t^2 + 64t = 48
-16t^2 + 64t - 48 = 0
Divide thru by -16 to get:
t^2 - 4t + 3 = 0
(t-3)(t-1) = 0
t = 1 sec or t = 3 seconds
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At 1 sec and at 3 seconds theobjectwas 48 ft above the ground.
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Cheers,
Stan H.
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