SOLUTION: how to you put {{{ (x^2/.0625)+(y+3)^2/.25=1 }}} into a y= form?(for a calculator) the equation is for an ellipse

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: how to you put {{{ (x^2/.0625)+(y+3)^2/.25=1 }}} into a y= form?(for a calculator) the equation is for an ellipse      Log On


   

Question 176062: how to you put +%28x%5E2%2F.0625%29%2B%28y%2B3%29%5E2%2F.25=1+ into a y= form?(for a calculator)
the equation is for an ellipse
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
subtracting (x^2 / .0625) __ (y+3)^2 / .25 = 1 - (x^2 / .0625)

multiplying by .25 __ (y+3)^2 = .25 - 4x^2

taking squareroot __ y+3 = ± sqrt(.25 - 4x^2)

subtracting 3 __ y = -3 ± sqrt(.25 - 4x^2)


don't know if the calculator will take the ±
you may have to do it in two parts; one + and one -