SOLUTION: I'm stumped on 2 word problems dealing with probability. Can someone please help me???? Here they are: 1. Suppose a contest offers $1,000 to the person who can guess the winnin

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Question 175812: I'm stumped on 2 word problems dealing with probability. Can someone please help me????
Here they are:
1. Suppose a contest offers $1,000 to the person who can guess the winning four digit number. How many possibilities are there?
2. There are 10 women and 8 men in a club. How many different committees of 6 people can be selected from the group if equal numbers of men and women are to be on the committee?
TIA for your help!
Andrew
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
1. Suppose a contest offers $1,000 to the person who can guess the winning four digit number. How many possibilities are there?
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# of four-digit numbers: 1000-9999= 8999+1 = 9000
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2. There are 10 women and 8 men in a club. How many different committees of 6 people can be selected from the group if equal numbers of men and women are to be on the committee?
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6 on the committe requires 3 men and 3 women.
# of groups of 3 women: 10C3 = [10*9*8]/[1*2*3] = 120
# of groups of 3 men : 8C3 = 8*7*6/1*2*3 = 56
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# of possible committees: 120*56 = 6720
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Cheers,
Stan H.