SOLUTION: Find the additive inverse of each number 1.) 3-7i 2.) -2 + i

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Question 175626: Find the additive inverse of each number
1.) 3-7i
2.) -2 + i

Found 2 solutions by Mathtut, solver91311:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
3-7i..additive inverse is -3+7i
-2+i..additive inverse is 2-i
:
together the complex number added to its additive inverse should equal
:
0+0i

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
The additive inverse of any number s is that number when added to the original number results in 0, in other words -s. That is because s+%2B+%28-s%29+=+0 for all s.

In order to add two complex numbers, you add the real parts and then add the real coefficients of the imaginary parts, thus:

%28a+%2B+bi%29+%2B+%28c+%2B+di%29+=+%28%28a+%2B+c%29+%2B+%28b+%2B+d%29i%29

Hence, if you are trying to find the additive inverse of a complex number you need to find the additive inverse of the real part and the additive inverse of the coefficient of the imaginary part.

Problem 1. +3+-+7i

The additive inverse of 3 is -3 and the additive inverse of -7 is 7 so the additive inverse of +3+-+7i must be -3+%2B+7i.

Check:

Do the other problem the same way.