SOLUTION: Graph each function. State the vertex and the y-intercept. Find its maximum or minimum value. 1.) y = -(x-2)^2 + 1 2.) y = -x^2 + 7

Algebra ->  Graphs -> SOLUTION: Graph each function. State the vertex and the y-intercept. Find its maximum or minimum value. 1.) y = -(x-2)^2 + 1 2.) y = -x^2 + 7      Log On


   



Question 175623: Graph each function. State the vertex and the y-intercept. Find its maximum or minimum value.
1.) y = -(x-2)^2 + 1
2.) y = -x^2 + 7

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the general equation is
y+=+ax%5E2+%2B+bx+%2B+c
The vertex is at -%28b%2F2a%29
1) y+=+-%28x-2%29%5E2+%2B+1
y+=+-%28x%5E2+-+4x+%2B+4%29+%2B+1
y+=+-x%5E2+%2B+4x+-+3
-%28b%2F%282a%29%29+=+-%284%2F%282%2A%28-1%29%29%29
4%2F2+=+2
When x=2,y=1, so the
vertex is at (2,1)
It's a max because of the - sign
in front of (x-2)^2
Graphing the 2 equations:
+graph%28+600%2C+600%2C+-10%2C+10%2C+-5%2C+10%2C-x%5E2+%2B+4x+-+3%2C-x%5E2+%2B+7%29+