SOLUTION: Bob has in his pockets a number of pennies, five times as many nickels as pennies, and 6 more quarters than pennies. The coins amount to a value of $2.52. Find The number of pennie

Algebra ->  Expressions-with-variables -> SOLUTION: Bob has in his pockets a number of pennies, five times as many nickels as pennies, and 6 more quarters than pennies. The coins amount to a value of $2.52. Find The number of pennie      Log On


   

Question 175619: Bob has in his pockets a number of pennies, five times as many nickels as pennies, and 6 more quarters than pennies. The coins amount to a value of $2.52. Find The number of pennies.
Found 2 solutions by josmiceli, EMStelley:
Answer by josmiceli(19441) About Me  (Show Source):
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Let p= number of penniew
Let n= number of nickels
Let q= number of quarters
given:
(1) n+=+5p
(2) q+=+p+%2B+6
(3) p+%2B+5n+%2B+25q+=+252 (in terms of pennies)
Substituting:
(3) p+%2B+5%2A%285p%29+%2B+25%2A%28p%2B6%29+=+252
p+%2B+25p+%2B+25p+%2B+150+=+252
51p+=+102
p+=+2
He has 2 pennies
check:
n+=+5p
n+=+10
q+=+p+%2B+6
q+=+8
(3) 2+%2B+5%2A10+%2B+25%2A8+=+252
2+%2B+50+%2B+200+=+252
252+=+252
OK

Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
Call the number of pennies P. Then the number of nickels is 5P and the number of quarters is P+6. The dollar amount of pennies is 0.01P, nickels is 0.05(5P) and quarters is 0.25(P+6). Thus we have
0.01P + 0.05(5P) + 0.25(P+6) = 2.52
0.01P + 0.25P + 0.25P + 1.50 = 2.52
0.51P + 1.50 = 2.52
0.51P = 1.02
P = 2
Thus Bob has 2 pennies.