SOLUTION: Sally has seven times as many dimes as nickels. Their value is $3.00. How many nickels does she have?

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Question 175614: Sally has seven times as many dimes as nickels. Their value is $3.00. How many nickels does she have?
Found 3 solutions by EMStelley, Mathtut, solver91311:
Answer by EMStelley(208) About Me  (Show Source):
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Call the number of nickels n. Then the number of dimes is 7n. The value of the amount of nickels is 0.05n because each nickel is worth $0.05. Thus the value of the amount of dimes is 0.10(7n) for the same reason.
So
0.05n+%2B+0.10%287n%29+=+3.00
0.05n+%2B+0.70n+=+3.00
0.75n+=+3.00
n+=+4
Thus Sally has 4 nickels and 28 dimes.

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call the # of dimes and nickels , d and m, respectively
:
d=7n.....eq 1
.1d+.05n=3....eq 2
:
take d's value of 7n in eq 1 and plug it into eq 2
:
.1(7n)+.05n=3
:
.75n=3
:
highlight%28n=4%29nickels
:
highlight%28d=7%284%29=28%29dimes

Answer by solver91311(24713) About Me  (Show Source):
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Number of nickels: n

Number of dimes: d

We know that d+=+7n because Sally has seven times as many dimes as nickels.

Each of Sally's nickels is worth 5 cents, so the value, in cents, of all of Sally's nickels is 5n. Likewise, the value, in cents, of all of Sally's dimes is 10d.

We know that the total value of Sally's coins is $3.00, but we can also say that the total value of her coins is 300 cents. Now we can write:

5n+%2B+10d+=+300

But since we also know that d+=+7n, we can substitute 7n for d:

5n+%2B+10%287n%29+=+300

Solving:

5n+%2B+70n+=+300

75n+=+300

n+=+300%2F75+=+4

Therefore Sally has 4 nickels.

Check: If Sally has 4 nickels, she must have 7+%2A+4+=+28 dimes. 28 dimes are worth $2.80 and 4 nickels are worth $0.20 and $2.80 plus $0.20 is $3.00. Answer checks.