SOLUTION: The length of a rectangle is five inches more than its width. The perimeter is 66 inches. Find the dimensions of the rectangle.

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Question 175404: The length of a rectangle is five inches more than its width. The perimeter is 66 inches. Find the dimensions of the rectangle.
Found 2 solutions by EMStelley, Mathtut:
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
Let's call the width of the rectangle w. Then we can denote the length of the rectangle by w+5 since the length is 5 inches more than its width. Remembering that the perimeter equation is 2*length + 2*width, we get that
2w+%2B+2%28w%2B5%29+=+66
So
2w+%2B+2w+%2B+10+=+66
Combining like terms and subtracting 10 yields
4w+=+56
Dividing both sides by 4, we get
w+=+14
So the width of the rectangle is 14 inches. Using the knowledge we have about the length, that means the length is 19 inches.

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
W is width L=W+5 Perimeter =66
:
66=2W+2(W+5)
:
66=2W+2W+10
:
4W=56
:
highlight%28W=14%29inches
:
highlight%28L=W%2B5=14%2B5=19%29inches