You can put this solution on YOUR website! can you please help me solve: (((n^3-27/n-3)))
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This can't be solved, but it can be simplified.
Notice that in the NUM, both terms are the third power, n^3 and 3^3. Any binomial with odd exponents can be factored.
You can always just divide it out, too, with long division of synthetic division.
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The (n-3)'s cancel, so
it's
