SOLUTION: Two consecutive even integers such that seven times the first exceeds five times the second by 54.
Here is what I tried.
First Number = 7x+5
Second = x/54
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Here is what I tried.
First Number = 7x+5
Second = x/54
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Question 175311: Two consecutive even integers such that seven times the first exceeds five times the second by 54.
Here is what I tried.
First Number = 7x+5
Second = x/54
You can put this solution on YOUR website! Two consecutive even integers such that seven times the first exceeds five times the second by 54.
Here is what I tried.
let the two numbers be a and b=a+2
:
7a-5(a+2)=54
:
7a-5a-10=54
:
2a=64
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