SOLUTION: i am so confused: 5) (3x-4)(x+5) 6) (x+2)(x²+x+5) 7) (x+1)(x³+4x²+7x+3)

Algebra ->  Expressions -> SOLUTION: i am so confused: 5) (3x-4)(x+5) 6) (x+2)(x²+x+5) 7) (x+1)(x³+4x²+7x+3)       Log On


   



Question 175186: i am so confused:
5) (3x-4)(x+5)

6) (x+2)(x²+x+5)

7) (x+1)(x³+4x²+7x+3)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
i am so confused:
5) (3x-4)(x+5)
6) (x+2)(x²+x+5)
7) (x+1)(x³+4x²+7x+3)
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You didn't say what you want to do. I'll guess it's multiply, so
5) (3x-4)(x+5)
= 3x*(x+5) - 4*(x+5) Multiply each element by the other binomial
= 3x^2+15x - 4x-20
Collect like terms, that is, all x^2 terms, x terms, etc
=3x%5E2+%2B+11x+-+20
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7) (x+1)(x³+4x²+7x+3)
= x*(x³+4x²+7x+3) + 1*(x³+4x²+7x+3)
= x%5E4%2B4x%5E3%2B7x%5E2%2B3x+%2B+x%5E3%2B4x%5E2%2B7x%2B3
Collect like terms (terms with the same exponent)
=x%5E4+%2B+5x%5E3+%2B+11x%5E2+%2B+10x+%2B+3
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You do #6. If you have questions, email me (the thank you note sends me email)