Question 175036: find two consecutive odd number such that when smaller number is subtracted from 3 time bigger number, the result is 56. Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Let x=the first odd number
Then x+2=the second or bigger odd number
3(x+2)=three times the bigger odd number
Now we are told the following:
3(x+2)-x=56 get rid of parens (distributive)
3x+6-x=56 subtract 6 from each side
3x+6-6-x=56-6 collect like terms
2x=50 divide each side by 2
x=25--------------------------first odd number
x+2=25+2=27-----------------------second odd number
CK
3*27-25=56
81-25=56
56=56
Does this help?---ptaylor
