Question 174996: If a line passes through the point (-1,3) and has a slop of 2. How do I find another point?
Found 3 solutions by Alan3354, Mathtut, actuary:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! If a line passes through the point (-1,3) and has a slop of 2. How do I find another point?
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One way is to find the equation, then find any number of points.
Use y-y1 = m*(x-x1) where m is the slope and (x1,y1) is the point (-1,3)
y-3 = 2*(x+1) = 2x+2
y = 2x + 5
Then insert a value for x and find y
eg, x=0, y=5 --> (0,5)
x= 1/3, y = 17/3 --> (1/3,17/3)
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Another way is to add/subtract 2 to y for each 1 to x.
Points = (-1+2q,3+q) for any value of q
Answer by Mathtut(3670)  (Show Source):
You can put this solution on YOUR website! you have to find the equation of the line then you can find any point. Use the point slope formula which states y-k=m(x-h) where m is the slope and (h,k) is any point on the line
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y-3=2(x-(-1))
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y-3=2x+2
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y=2x+5
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now just choose any value of x or y and solve for the unknown...I choose x=0
y=2(0)+5--->y=5
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so for x=0,y=5--->point(0,5)
Answer by actuary(112) (Show Source):
You can put this solution on YOUR website! First write the equation of the line
In point slope form, the equation is
y-3=2*(x-(-1))
This can be written in slope y-intercept form
y=2*x+2+3 = 2*x+5
This line goes through the point(-1,3)
Select the "x" value for another point, say x=2.
Replace the variable "x" in the equation with the value of x which is 2.
Y= 2*2+5=9
So another point on the line is (2,9)
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