SOLUTION: how do i find the value of x in the equation x/2+20=15+x/3?

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Question 174957: how do i find the value of x in the equation x/2+20=15+x/3?
Found 3 solutions by Mathtut, stanbon, Electrified_Levi:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2F2%29%2B20=15%2B%28x%2F3%29.....multiply all terms by least common denominator which is 6
:
3x%2B120=90%2B2xsubtract 2x and 120 from both sides
:
highlight%28x=-30%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the value of x in the equation x/2+20=15+x/3?
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x/2 - x/3 = -5
(3x-2x)/6 = -5
x = -30
==================
Cheers,
Stan H.

Answer by Electrified_Levi(103) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, Hope I can help,
.
how do i find the value of x in the equation +x%2F2%2B20=15%2Bx%2F3+ ?
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First of all, we have to get rid of the fractions
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We have to find a common denominator with the fractions
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The first fraction, +x%2F2+, has "2" as its denominator
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The second fraction, +x%2F3+, has "3" as its denominator
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To find the common denominator, we would just multiply the two denominators together ( since there is no lower denominator we could use )
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+2%283%29+ = +6+
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"6" is the common denominator, now if we multiply the two sides of the equation, it will get rid of the fractions, since they both will cancel out
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+x%2F2%2B20=15%2Bx%2F3+ = +6%28x%2F2%2B20%29=6%2815%2Bx%2F3%29+
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We can now use the distributive property,
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= = +6%28x%2F2%29%2B+6%2820%29=6%2815%29%2B+6%28x%2F3%29+
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+6%28x%2F2%29%2B+6%2820%29=6%2815%29%2B+6%28x%2F3%29+ = +6x%2F2%2B+120+=+90+%2B+6x%2F3+, now we will simplify even further by dividing
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+6x%2F2%2B+120+=+90+%2B+6x%2F3+ = +%282%283x%29%29%2F2%2B+120+=+90+%2B+%283%282x%29%29%2F3+ = = = +3x+%2B+120+=+90+%2B+2x+
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Now all we do is solve for "x", we will move "2x" to the left side
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+3x+%2B+120+=+90+%2B+2x+ = +3x+-+2x+%2B+120+=+90+%2B+2x+-+2x+ = +x+%2B+120+=+90+, now we will move "120" to the right side
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+x+%2B+120+=+90+ = +x+%2B+120+-+120+=+90+-+120+ = +x+=+%28-30%29+
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+x+=+%28-30%29+
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You can check by replacing "x" with (-30) in the very original equation
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replace "x" with (-30), +x%2F2%2B20=15%2Bx%2F3+ = +%28-30%29%2F2%2B20=15%2B%28-30%29%2F3+ = +%28-15%29%2B20=15+-+30%2F3+ = +%28-15%29%2B20=15+-+10+ = +5+=+5+ ( True )
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You have to be careful with fraction equations, because the denominator of a fraction cannot equal 0, so if one of the answers make a denominator 0, then that answer cannot work
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We don't have anything to worry about, since there are no "x"'s in the denominator
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+x+=+%28-30%29+
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Hope I helped, Levi