SOLUTION: Find the inverse of {{{ matrix(1,3, A, "=", (matrix(2,2,-3,1,-5,5)) ) }}} if it exists.

Algebra ->  Rational-functions -> SOLUTION: Find the inverse of {{{ matrix(1,3, A, "=", (matrix(2,2,-3,1,-5,5)) ) }}} if it exists.      Log On


   



Question 174894This question is from textbook saxon algebra 2
: Find the inverse of +matrix%281%2C3%2C+A%2C+%22=%22%2C+%28matrix%282%2C2%2C-3%2C1%2C-5%2C5%29%29++%29+ if it exists. This question is from textbook saxon algebra 2

Answer by Edwin McCravy(20063) About Me  (Show Source):
You can put this solution on YOUR website!
Find the inverse of A = %28matrix%282%2C2%2C-3%2C1%2C-5%2C5%29%29 if it exists.

Method 1:

Start with the matrix:
+matrix%281%2C3%2C+A%2C+%22=%22%2C+%28matrix%282%2C2%2C-3%2C1%2C-5%2C5%29%29++%29+

Augment it on the right with the identity matrix, %28matrix%282%2C2%2C1%2C0%2C0%2C1%29%29%29,
like this


 
Now we do row operations to get the identity on the left:

To get a zero where the -5 is,

Add -5 times row 1 to 3 times row 2.  It's a good idea
to write the number you're multiplying row by, on
the far left:

matrix%282%2C1%2C-5%2C3%29

The result is:



Next we get a zero where the 1 is in row 1, column 2
by adding 1 times row 2 to -10 times row 1.

matrix%282%2C1%2C-10%2C1%29

The result is:


 
Get a 1 where the 30 is by multiplying row 1
by 1%2F30

Get a 1 where the 10 is by multiplying row 2
by 1%2F10

matrix%282%2C1%2C1%2F30%2C1%2F10%29

The result is:


 
So the inverse of A or A%5E%28-1%29 is the part on the right:



That method works for all matrices.

------------------------------------

Here's a method that works only for 2x2 matrices:

Method 2:

Start with the matrix:

%28matrix%282%2C2%2C-3%2C1%2C-5%2C5%29%29

Find the determinant of the matrix:



Swap the upper left and lower right elements:

%28matrix%282%2C2%2C5%2C1%2C-5%2C-3%29%29

Change the signs of the upper right and lower left elements:

%28matrix%282%2C2%2C5%2C-1%2C5%2C-3%29%29

Divide every element by the -10 which was the determinant of the
original matrix:



Simplify the fractions:



Edwin