SOLUTION: (17) If 3sin^2(theta) - 4sin(theta) + 1 = 0, find all values of (theta) to the nearest minute in the interval 0 < x < 360. show work, thank you so much, i appreciate it alot

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: (17) If 3sin^2(theta) - 4sin(theta) + 1 = 0, find all values of (theta) to the nearest minute in the interval 0 < x < 360. show work, thank you so much, i appreciate it alot       Log On


   

Question 174834This question is from textbook Amsco's Preparing for the Regents Examination Mathematics B
: (17) If 3sin^2(theta) - 4sin(theta) + 1 = 0, find all values of (theta) to the nearest minute in the interval 0 < x < 360.

show work, thank you so much, i appreciate it alot This question is from textbook Amsco's Preparing for the Regents Examination Mathematics B

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = sin theta
3a%5E2+-+4a+%2B+1+=+0
a+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a+=+%28-%28-4%29+%2B-+sqrt%28+%28-4%29%5E2-4%2A3%2A1+%29%29%2F%282%2A3%29+
a+=+%284+%2B-+sqrt%2816+-+12+%29%29%2F6+
a+=+%284+%2B-+sqrt%284%29%29%2F6+
a+=+1
a+=+1%2F3
sin theta = 1
(1) theta = 90 degrees
sin theta = 1/3
(2) theta = 19 degrees 28 min
(3) theta = 199 degrees 28 min