SOLUTION: 8m^3 + 27/ 2m+3
answer:4m^2-6m+9
need a full break down of how my book got this answer i know how they got 4m^2 and +9 but still lost as to how they got the -6m
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: 8m^3 + 27/ 2m+3
answer:4m^2-6m+9
need a full break down of how my book got this answer i know how they got 4m^2 and +9 but still lost as to how they got the -6m
Log On
need a full break down of how my book got this answer i know how they got 4m^2 and +9 but still lost as to how they got the -6m Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! In this problem, you need to factor the numerator by applying the special factor condition known as the "sum of cubes". For a complete explanation see:
http://www.purplemath.com/modules/specfact2.htm
.
is equivalent to:
.
Now, we can apply the "sum of cubes" rule of:
a^3 + b^3 = (a + b)(a^2 – ab + b^2)
.
The (2m+3) cancels leaving:
Expanding:
