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Question 174626This question is from textbook Amsco's Preparing for the Regents Examination Mathematics B
: 4.) If sin(2theta + 18) = cos(5theta - 12), which of the follwoing pairs of angles are represented in this equation?
(a)42, 48 degrees
(b)38, 52 degrees
(c) 12, 68 degrees
(d) 45, 45 degrees
5) Crossing a wooden bridge at Letchworth Park, Melissa drops a penny into the water below for good luck. If the height of the penny is modeled by the function h(t)=64 - 16t^2, where t represents time in seconds and h(t) is height in feet, how many seconds did it take the penny to hit the water?
(a) 1 (b) 2 (c) 3 (d) 4
Sh0w work thanks so much!
This question is from textbook Amsco's Preparing for the Regents Examination Mathematics B
Answer by nycsub_teacher(90)   (Show Source):
You can put this solution on YOUR website! 5) Crossing a wooden bridge at Letchworth Park, Melissa drops a penny into the water below for good luck. If the height of the penny is modeled by the function h(t)=64 - 16t^2, where t represents time in seconds and h(t) is height in feet, how many seconds did it take the penny to hit the water?
(a) 1 (b) 2 (c) 3 (d) 4
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Let h(t) = 0
0 = 64 - 16t^2
All you have to do is solve for t.
Can you take it from here?
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Hello. I received your e-mail. You need more help, right?
Here is one of your questions:
(5) Crossing a wooden bridge at Letchworth Park, Melissa drops a penny into the water below for good luck. If the height of the penny is modeled by the function h(t)=64 - 16t^2, where t represents time in seconds and h(t) is height in feet, how many seconds did it take the penny to hit the water?
(a) 1 (b) 2 (c) 3 (d) 4
Let h(t) = 0
0 = 64 - 16t^2
Subtract 64 from both sides.
-64 = -16t^2
Now divide both sides by -16.
-64/-16 = t^2
64/16 = t^2
4 = t^2
Finally take the square root of both sides of the equation.
sqrt{4} = sqrt{t^2}
2 = t
The answer is choice (b).
Do you need help with the trig equation question?
Happy new year!
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