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Question 174586: Find the Equation for the line with given properties:
Parallel to the lines 5x+2y=10; containing the point (4,-4)
Perpendicular to the line x-6y=6; containing (4,4)
Perpendicular to the line 4x-7y=-56; containing the point (-7,-4)
Perpendicular to the line -5x+6y=4; y - intercept =3
Perpendicular to the line 6x-3y=8; containing the point (0,8)
Find the midpoint of the line segment joining the points P1 and P2:
P1=(y,7); P2= (0,2)
I could really use the help for these problems....Thank you...I am stuck
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! For each problem you need slope and intercept.
The form is always y = mx + b; m is the slope; b is the intercept.
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Find the Equation for the line with given properties:
Parallel to the lines 5x+2y=10; containing the point (4,-4)
slope = -5/2 ;
intercep: -4 = (-5/2)*4 = b
b = 6
Equation: y = (-5/2)x + 6
Same Equation: 2y + 5x = 12
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Perpendicular to the line x-6y=6; containing (4,4)
Given line slope: (1/6)
Perpendicular line slope: -6
intercept: 4 = -6*4 + b
b = 28
Equation: y = -6x + 28
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Perpendicular to the line 4x-7y=-56; containing the point (-7,-4)
Given line slope: (4/7)
Perpendicular line slope: -7/4
intercept: -4 = (-7/4)*-7 + b
b = -53/4
EQuation: y = (-7/4)x - (53/4)
Same Equation: 4y + 7x = -53
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Perpendicular to the line -5x+6y=4; y-intercept =3
Given line slope: 5/6
Perpendicular line slope: -6/5
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intercept: y = 3
Equation: y = (-6/5)x + 3
Same Equation: 5y+6x = 15
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Perpendicular to the line 6x-3y=8; containing the point (0,8)
Given line slope: 6/3 = 2
Perpendicular line slope: -1/2
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Intercept: 8 = (-1/2)*0 = b
b = 8
Equation: y = (-1/2)x + 8
Same Equation: 2y + x = 16
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Find the midpoint of the line segment joining the points P1 and P2:
P1=(y,7); P2= (0,2)
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The x-coordinate of the mid-point is the average of the x-coordinates
of the end points.
The y-coordinate of the mid-point is the average of the y-coordinates
of the end points.
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mid-point: ((y+0)/2 , (7+2)/2) or (y/2, 9/2)
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Cheers,
Stan H.
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