SOLUTION: Please help me : find the total numbers of nine digit numbers which have all different digits.

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Question 174518: Please help me :

find the total numbers of nine digit numbers which have all different digits.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The highest order digit must be 1-9 (it can't be 0)
so, there are 9 choices
The next digit can be 0-9, minus the choice I just made
So far I have
9%2A9+=+81 choices
There are 8 choices for the 3rd digit,
7 for the 4th
6 for the 5th
5 for the 6th
4 for the 7th
3 for the 8th
2 for the 9th
The number of possible 9 digit numbers with different digits is is
9%2A9%2A8%2A7%2A6%2A5%2A4%2A3%2A2+=+3265920 answer