You can put this solution on YOUR website! what is the solution for (x^5-y^5)/(x-y)
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Ans: x^4 + x^3y + x^2y^2 + xy^4 + y^4
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Cheers,
Stan H.
Most people learn the factorization of .
But if you forget you can divide that problem out using long division:
x4 + x3y + x2y2 + xy3 + y4
---------------------------------------
x - y ) x5 + 0x4y + 0x3y2 + 0x2y3 + 0xy4 - y5
x5 - x4y
---------
x4y + 0x3y2
x4y - x3y2
-----------
x3y2 + 0x2y3
x3y2 - x2y3
------------
x2y3 + 0xy4
x2y3 - xy4
-----------
xy4 - y5
xy4 - y5
--------
0
So the answer is
x4 + x3y + x2y2 + xy3 + y4
However if you memorize how to factor , i.e.,
then you will know how to factor . Then to simplify
the expression
you will just factor the numerator according to the rule above:
.
One thing to remember though, is that although that factorization
method holds for all values of N, it only factors COMPLETELY when
N is an ODD positive integer. When N is EVEN, you should always
begin by factoring it as the difference of two squares.
Edwin