SOLUTION: During a halftime show, a baton twirler releases her baton from a point 4 feet above the ground with an initial vertical velocity of 25 feet per second. Use a vertical motion mode

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Question 174451This question is from textbook Algebra 2, Texas Edition
: During a halftime show, a baton twirler releases her baton from a point 4 feet above the ground with an initial vertical velocity of 25 feet per second. Use a vertical motion model to write a function for the height h (in feet) of the baton after t seconds then graph the function and label the vertex.
Please show all work possible and any strategies used in depth. Thank You for your time and help! =) Hope to hear from you soon.
This question is from textbook Algebra 2, Texas Edition

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
During a halftime show, a baton twirler releases her baton from a point 4 feet
above the ground with an initial vertical velocity of 25 feet per second.
Use a vertical motion model to write a function for the height h (in feet)
of the baton after t seconds then graph the function and label the vertex.
:
Write an equation for this using the three elements involved here
t = time in seconds
Gravity: -16t^2, negative because it's pulling downward
Velocity upward: +25t
Initial height: 4 ft
;
h(t) = -16t^2 + 25t + 4
:
Vertex occurs at the axis of symmetry,formula for this: x = %28-b%29%2F%282a%29
find the time of the highest point a=-16; b=25:
t = %28-25%29%2F%282%2A-16%29
t = %28-25%29%2F%28-32%29
t = +.78125 sec
:
Substitute for t in the equation to find h(t)
h(t) = -16(.78125^2) + 25(.78125) + 4
h(t) = -16(.61035) + 19.53125 + 4
h(t) = -9.7656 + 23.53125
h(t) = 13.76565 ft
:
A graph of this:
+graph%28+300%2C+200%2C+-2%2C+3%2C+-4%2C+20%2C+-16x%5E2%2B25x%2B4%29+
:
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