SOLUTION: {xy^5/x^-4y^2]^-2
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Question 174421
:
{xy^5/x^-4y^2]^-2
Answer by
stanbon(75887)
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{xy^5/x^-4y^2]^-2
Working from the inside to the outside:
= (x^5*y^3)^-2
= 1/(y^6*x^10)
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Cheers,
Stan H.