SOLUTION: 38) find all solution between 0 through 2pi 2sin^2x+ 3sinx+1=0

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Question 174403: 38) find all solution between 0 through 2pi
2sin^2x+ 3sinx+1=0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find all solution between 0 through 2pi
2sin^2x+ 3sinx+1=0
Factor to get:
(2sin(x)+1)(sin(x)+1) = 0
sin(x) = -1/2 or sin(x) = -1
x = (7/6)pi or (11/6)pi or (3/2)pi
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Cheers,
Stan H.