SOLUTION: write the expression as a single logarithm: 2logbw+3logby
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Question 174376
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write the expression as a single logarithm: 2logbw+3logby
Found 2 solutions by
stanbon, josmiceli
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Answer by
stanbon(75887)
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2logbw + 3logby
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The "b" in this case is the base of the logs.
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logb (w^2) + logb (y^3)
= logb [w^2*y^3]
Cheers,
Stan H.
Answer by
josmiceli(19441)
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answer
To see this more clearly, substitute some simple numbers
and, from above,