Question 174301: compute the geometric and harmonic means for the following distribution of annual death rates:
xi[3.95,4.95,5.95,6.95,7.95,8.95,9.95,10.95,11.95,12.95,13.95]
Fi[1 ][ 4][5 ][13 ][12] [19] [13] [10] [6 ] [4 ] [ 1 ]
Answer by Edwin McCravy(20081) (Show Source):
You can put this solution on YOUR website! compute the geometric and harmonic means for the following distribution of annual death rates:
xi[3.95,4.95,5.95,6.95,7.95,8.95,9.95,10.95,11.95,12.95,13.95
You just have to learn some rules about the different kinds of averaging:
You didn't ask about arithmetic mean, but we have to use it
to find the harmonic mean.
How to find the arithmetic mean of some numbers:
1. Count them.
2. Add them all together.
3. Divide the result of 2 by the result of 1.
How to find the geometric mean of some numbers:
1. Count them.
2. Multiply them all together.
3. Take the root corresponding to 1 of the result of 1.
How to find the harmonic mean of some numbers:
1. Take the reciprocals of all the numbers
2. Take the arithmetic mean of the results of 1
3. Take the reciprocal of the result of 2.
3.95,4.95,5.95,6.95,7.95,8.95,9.95,10.95,11.95,12.95,13.95
To find the geometric mean:
1. Count them.
There are 11 of them
2. Multiply them all together.
(3.95)(4.95)(5.95)(6.95)(7.95)(8.95)(9.95)(10.95)(11.95)(12.95)(13.95)
= 1.353141797 × 1010.
3. Take the root corresponding to 1 of the result of 1.
Since we counted 11 in the first step, we take the 11th root:
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To find the harmonic means:
1. Take the reciprocals of all the numbers:
, , , , , , , , , ,
2. Take the arithmetic mean of the results of 1
To find the arithmetic mean of those numbers:
1a. Count them. There are 11
2a. Add them all together. 1.19694482
3a. Divide the result of 2 by the result of 1a.
3. Take the reciprocal of the result of 2.
Edwin
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