SOLUTION: 1. find the x and y intercepts for 6x-4y=12 2. find the equation of a line that contains the point (0,2) and has a slope -3. 3. find the equation of a line that contains the

Algebra ->  Expressions -> SOLUTION: 1. find the x and y intercepts for 6x-4y=12 2. find the equation of a line that contains the point (0,2) and has a slope -3. 3. find the equation of a line that contains the       Log On


   



Question 174263: 1. find the x and y intercepts for 6x-4y=12
2. find the equation of a line that contains the point (0,2) and has a slope -3.
3. find the equation of a line that contains the point(1,0) and has a slope of 2.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first two to get you started

# 1



x-intercept


To find the x-intercept, plug in y=0 and solve for x


6x-4y=12 Start with the given equation.


6x-4%280%29=12 Plug in y=0.


6x-0=12 Multiply -4 and 0 to get 0.


6x=12 Simplify.


x=%2812%29%2F%286%29 Divide both sides by 6 to isolate x.


x=2 Reduce.


So the x-intercept is .


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y-intercept


To find the y-intercept, plug in x=0 and solve for y


6x-4y=12 Start with the given equation.


6%280%29-4y=12 Plug in x=0.


0-4y=12 Multiply 6 and 0 to get 0.


-4y=12 Simplify.


y=%2812%29%2F%28-4%29 Divide both sides by -4 to isolate y.


y=-3 Reduce.


So the y-intercept is .







# 2




If you want to find the equation of line with a given a slope of -3 which goes through the point (0,2), you can simply use the point-slope formula to find the equation:


---Point-Slope Formula---
y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope, and is the given point

So lets use the Point-Slope Formula to find the equation of the line

y-2=%28-3%29%28x-0%29 Plug in m=-3, x%5B1%5D=0, and y%5B1%5D=2 (these values are given)


y-2=-3x%2B%28-3%29%28-0%29 Distribute -3

y-2=-3x%2B0 Multiply -3 and -0 to get 0

y=-3x%2B0%2B2 Add 2 to both sides to isolate y

y=-3x%2B2 Combine like terms 0 and 2 to get 2
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Answer:


So the equation of the line with a slope of -3 which goes through the point (0,2) is:

y=-3x%2B2 which is now in y=mx%2Bb form where the slope is m=-3 and the y-intercept is b=2

Notice if we graph the equation y=-3x%2B2 and plot the point (0,2), we get (note: if you need help with graphing, check out this solver)

Graph of y=-3x%2B2 through the point (0,2)
and we can see that the point lies on the line. Since we know the equation has a slope of -3 and goes through the point (0,2), this verifies our answer.