SOLUTION: I have a complex fraction:
This fraction is the numerator: x/x+1
The denominator is: 1/x(exponent 2)-1 MINUS 1/x-1
Im pretty sure you have to find the LCD, but I don't kno
This fraction is the numerator: x/x+1
The denominator is: 1/x(exponent 2)-1 MINUS 1/x-1
Im pretty sure you have to find the LCD, but I don't know where to go from here.
Thank you for any help. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! This fraction is the numerator: x/x+1
The denominator is: 1/x(exponent 2)-1 MINUS 1/x-1
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[x/(x+1)] / [1/(x^2-1) - 1/(x-1)]
= [x/(x+1)] / [1 -(x+1)] / (x^2-1)]
= [x/(x+1)] / [-x / (x^2-1)]
Invert the denominator and multiply :
= [x/(x+1)] / [(x^2-1) /-x ]
Cancel where you can to get:
= [1/1] / [(x-1)/(-1)]
= (x-1)/(-1)
= 1-x
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Cheers,
Stan H.
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