SOLUTION: I really need help with this, I've been given the rules, but I don't under stand how to apply it. Thanks so much for your help! 1. Convert the following equations into logarith

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I really need help with this, I've been given the rules, but I don't under stand how to apply it. Thanks so much for your help! 1. Convert the following equations into logarith      Log On


   

Question 174242: I really need help with this, I've been given the rules, but I don't under stand how to apply it. Thanks so much for your help!
1. Convert the following equations into logarithmic form:
a. 6 = 2x (x is the exponent)
b. 9 = 6y (y is the exponent)
c. 7 = 3y (y is the exponent)
d. X = 5y (y is the exponent)
Found 2 solutions by Mathtut, josmiceli:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
x=b%5Ey means log%28b%2Cx%29=y
1. Convert the following equations into logarithmic form:
a. 6 = 2x (x is the exponent)
b. 9 = 6y (y is the exponent)
c. 7 = 3y (y is the exponent)
d. X = 5y (y is the exponent)
:
:
a. log%282%2C6%29=x
b. log%286%2C9%29=y
c log%283%2C7%29=y
d. log%285%2Cx%29=y

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The main thing to remember is this:
***** Logs are exponents! *****
Say or write it 10 times and you'll be fine
Ok, the 1st problem is
a) 6+=+2%5Ex
What's the log here? It's the exponent x
OK, now I can write
log = x
What is the rest of it? Logs need a base, the same as exponents, so
log (base 2) = x
The last bit of info is what the result is when 2 is raised
to the log (or exponent)x
You write it like this:
log%282%2C6%29=+x this says
x is a log
2 is the base
6 is the result
---------------------
b) 9+=+6%5Ey
log%286%2C9%29+=+y
y is a log
6 is the base
9 is the result
---------------------
You should be able to do the rest