Question 174236: 1. Find the equation of the line that passes through the points (-4,-11)and (-2,-3).
2. find the slope of the line containing the given points. P1(3,11), P2(6,17)
Multiply
3. (x^2-7x+5)(3x-3)
4. 6x^10-3x^8+1/x^4
Answer by Student3354(13)   (Show Source):
You can put this solution on YOUR website! 1. Find the equation of the line that passes through the points (-4,-11)
and(-2,-3).
|x y 1|
|-4 -11 1| = 0
|-2 -3 1|
x*(-11+3) -y*(-4+2) + 12-22 = 0
-8x +2y = 10
4x - y = -5
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2. find the slope of the line containing the given points. P1(3,11), P2(6,17)
slope, m, = (diff in y)/(diff in x)
m = (17-11)/(6-3)
m = 2
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Multiply
3. (x^2-7x+5)(3x-3) = 3x^3 - 24x^2 +36x - 15
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4. 6x^10-3x^8+1/x^4 = 6x^6 - 3x^4 + 1/x^4
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