SOLUTION: 1. At 5:00 a.m., a train leaves a station and travels at a rate of 35 mph. At 7:00 a.m., a second train leaves the same station on the same track and travels in the direction of t
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Question 174165: 1. At 5:00 a.m., a train leaves a station and travels at a rate of 35 mph. At 7:00 a.m., a second train leaves the same station on the same track and travels in the direction of the first train at a speed of 45 mph. At 8:00 a.m., how many miles seperate the two trains?
solve:
2. 1/3x-2=5 Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! For both trains, the same formula applies, but I'll write it
differently for each train so I keep track of each train's data =distance in miles = speed in mi/hr = elapsed time in hrs
For train a:
For train b:
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Given: mi/hr mi/hr
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I want to have
the start time for both trains the same, at 7 AM,
so I want to know how far train a has gone between
5 AM and 7 AM mi
Now the trains will both travel for 1 hr, 7 AM to 8 AM mi
------------ mi
------------ mi
So, train b has gained 10 mi on train a, but train a
already had a 70 mi head start on train b
Train a is 60 mi ahead of train b
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check answer:
For train a: mi
For train b: mi
The difference is 60 mi
