SOLUTION: Throwing a wrench: An angry construction worker throws his wrench from a height of 128 feet with an initial velocity of 32 feet per second. The height of the wrench above the gro

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Question 174164This question is from textbook Basic and Intermediate Algebra
: Throwing a wrench: An angry construction worker throws his wrench from a height of 128 feet with an initial velocity of 32 feet per second. The height of the wrench above the ground after t seconds is given by S(t)--16t^2-32t + 128.
a) What is the height of the wrench after 1 second?
b) How long does it take for the wrench to reach the ground?
I would like a confirmation or correction to my solutions below:
a) S= (-16t^2-32t+128)
-16-1^2(-32*1)+128
-16(1^2)+ or 1 32(1) + 128 = 80 ft
b) 0= -16t^2-32+128
-16t^2/-16 = 0
-16t^2/-16 = t^2
-32/-16 = +2
128/-16= -8
0=t^2+2t-8=
(t+4)*t-2 =0
t= -4 or t =2
t = 2 seconds
This question is from textbook Basic and Intermediate Algebra

Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
i believe you are correct.
i got the same answers, given that the original equation is:
s%28t%29+=+-16t%5E2+-+32t+%2B+128